Class-X
Pair
Of Linear Equations In Two Variables
- Solve 2x+3y=11 and 2x-4y=-24 and hence the value of ‘m’ and hence the value of ‘m’ for which y=mx+3.
- Solve 3x+2y=14 and –x+4y=7 and hence find the value of k for which 3x=2ky+6.
- Solve x-y=0.9 and 2(x+y)=11 and hence find the value of m for which y=mx-3.
- From the pair of linear equations in the following solution by substitution method:
- The path traced by two trains are given by equations x+2y-4=0 and 2x+4y-12=0.Will the path cross?
- If 1 is added to each of the two numbers to each of the two numbers, t heir ratio become 1:2 and when 5 is subtracted from each of these, the ratio becomes 5:11. Find the numbers
- A man rowing at the rate of 5 km per hour in still water takes thrice, as much time in going 40 km up the river as in going 40 km up the river as in going 40km up the river as in going 40 km down,Find the rate at which the river flows.
- Four kg of apples and 3 kg of guava together cost Rs.36.50 while 3 kg of apples cost and 2 kg of guava cost Rs. 26.50.What is the price per kg of apples and guava?
- Anu has only 10 paise and 50 paise coins in her purse. If the total number of coins is 17 and their total value is Rs.26.50.What is the price per kg of apples and guava?
- A horse and 2 cows together cost Rs.680 and a horse costs Rs.80 more than a cow, find the cost of each
- Ten years ago, father was twelve times as old as his son and ten years hence he will be twice as old as his son will be. Find their present ages.
- A’s present age is to B’s present age is 7:9. Twelve years ago, their ages were in the ratio 3:5.When would the ratio of their present ages be 6:7?
- Five years ago, I was thrice as old as my son and ten years later I shall be twice as old as my son. How old are we now?
Compiled by:-
Sanjeev Kumar Taneja
Mathematics District Resource Person
Ludhiana
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